5x²-7x+1 have the roots alpha and beta the find the value of 1/alpha³-1/beta³
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the question you have typed is wrong.
p(x) = 5x²-7x+1
alpha+beta = 7/5
alpha. beta = 1/5
1/alpha+1/beta => alpha+beta/alpha.beta
=> putting values
=> 7/5/1/5 => 7 .
How it helps you!
p(x) = 5x²-7x+1
alpha+beta = 7/5
alpha. beta = 1/5
1/alpha+1/beta => alpha+beta/alpha.beta
=> putting values
=> 7/5/1/5 => 7 .
How it helps you!
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hey
Answered by
2
Answer:
-234.68
Step-by-step explanation:
5x² - 7x +1
by using quadratic formula,
-b±√b²-4ac ÷ 2a,
⇒ 7±√ 49-4(5)(1) ÷ 2(5)
⇒ 7±√ 29 ÷ 10 (√29 = 5.38)
⇒ 7±5.38 ÷ 10
⇒ 7+5.38 ÷ 10
⇒ 1.238 or = alpha
⇒7-5.38 ÷ 10
⇒ 0.162 or =beta
⇒ 1/alpha³ - 1/beta³
⇒ 1÷(1238/1000)³ - 1÷ (162/1000)³
⇒ (1000/1238)³ - (1000/162)³
⇒1000000000/1897413272 - 1000000000-4251528
⇒0.52 - 235.20
⇒ -234.68
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