Question

5x²-7x+9 sum and product of the zeroes of given polynomial​

Answer 1

Answer:

Step-by-step explanation:

To Find -

A polynomial whose zeroes is 1/a and 1/3

Now,

3x² - 7x-6

>> 3x² + 2x - 9x - 6

>> x(3x + 2) - 3(3x + 2)

>> (x - 3)(3x + 2)

Zeroes are -

x - 3= 0 and 3x + 2 = 0

• x = 3 and x = -2/3

Now,

Let a = 3 and ß = -2/3

Then,

1/a = 1/3

and

1/3=1-2/3 = -3/2

Sum of zeroes :

1/3 + (-3/2)

>> 1/3 - 3/2

Let a = 3 and ß = -2/3

Then,

1/a = 1/3

and

1/3=1-2/3 = -3/2

Sum of zeroes :

1/3 + (-3/2)

>> 1/3 - 3/2

>> 2 - 9/6

»> -7/6

And

Product of zeroes :

1/3 × -3/2

• »> -1/2

For a Quadratic polynomial :

x² - (sum of zeroes)x+ product of zeroes

» x² - (-7/6)x + (-1/2)

» x² + 7/6x - 1/2

Hence,

The polynomial is x² + 7/6x - 1/2

Answer 2

Answer:

7/5 and 9/5

Step-by-step explanation:

sum of zeroes of the given polynimal 5x2-7x+9

-b/a= -(-7)/9= 7/9.

product of zeroes =c/a= 9/5.