5x2+8x-4=0 find zeros of the polynomial and verify the relation between thecoeffient
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Answer:
zeroes are 2/5 and -2
Step-by-step explanation:
5x² + 8x - 4 = 0
5x² + (10 - 2)x - 4 = 0
5x² + 10x - 2x - 4 = 0
5x(x + 2).-2(x + 2) = 0
(5x - 2)(x + 2) = 0
5x - 2 = 0 , x + 2 = 0
5x = 2 . x = -2
x = 2/5 , x = -2
verification
sum of zeroes = -b/a
2/5 + (-2) = -8/5
(2 - 10)/5 = -8/5
-8/5 = -8/5
product of zeroes = c/a
2/5 × (-2) = -4/5
-4/5 = -4/5
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