√5x²-x-√5=0 Find the value of discriminant for this equation.
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Hi ,
Compare √5x² - x - √5 = 0 with ax²+bx+c = 0,
we get
a = √5 , b = -1 , c = -√5
discreaminant ( D ) = b² - 4ac
D = ( -1 )² - 4 × √5 × ( - √5 )
D = 1 + 4 × 5
D = 1 + 20
D = 21
Therefore ,
discreaminant ( D ) = 21
I hope this helps you.
: )
Compare √5x² - x - √5 = 0 with ax²+bx+c = 0,
we get
a = √5 , b = -1 , c = -√5
discreaminant ( D ) = b² - 4ac
D = ( -1 )² - 4 × √5 × ( - √5 )
D = 1 + 4 × 5
D = 1 + 20
D = 21
Therefore ,
discreaminant ( D ) = 21
I hope this helps you.
: )
Answered by
1
Answer:
hope it helps you....
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