Question

5xsquare -4x-5 factorise

Answer 1

Discriminant = b²-4ac

where a= 5
b= -4
c= -5
D = 16-4(5)5
D= 16-100= -84

The discriminant of this quadratic equation is
-ve

so .....
this quadratic equation has no real roots

Hope this helps you....

Answer 2

Answer:

$(x-\frac{2+\sqrt{29}}{5})(x-\frac{2-\sqrt{29}}{5})$

Step-by-step explanation:

GIVEN : $5x^{2} -4x-5$

To Solve : Factorise

Solution :

general form of equation is : $ax^{2} +bx+c=0$

Comparing the given equation we can see that :

a = 5

b = -4

c=-5

Now the general solution of quadratic equation is :

$x=\frac{-b\pm\sqrt{D} }{2a}$ ---(a)

where D is Discriminant

 $D= b^{2} -4ac$ ---(b)

Putting all value in (b)

 $D= (-4)^{2} -4*5*(-5)$

$D=16 +100$

$D=116$

Putting values in (a)

$x=\frac{4\pm\sqrt{116} }{2*5}$

$x=\frac{4\pm 2\sqrt{29}}{10}$

$x=\frac{2\pm \sqrt{29}}{5}$

$x=\frac{2+ \sqrt{29}}{5} , \frac{2-\sqrt{29}}{5}$

Thus $(x-\frac{2+\sqrt{29}}{5})(x-\frac{2-\sqrt{29}}{5})$