Question

х+у= 5xy ; 3х + 2y = 13 ху, x ≠ 0,
У≠0​

Answer 1

Answer:

x= 1/2 , y= 1/3

Step-by-step explanation:

x+y =5xy

=> (x/xy)+(y/xy) = 5xy/xy

=> 1/y +1/x = 5

=> 1/x + 1/y = 5.................(1)

3x+2y = 13xy. x,y ≠0

=> (3x/xy)+(2y/xy) = 13xy/xy

=> 3/y + 2/x = 13

=> 2/x+3/y = 13...................(2)

eqn(1)×2 - eqn(2)

=> 1/y = 3

=> y = 1/3

substituting the value of y in eqn (1)

=> 1/x+3 = 5

=> 1/x = 2

=> x = 1/2

Hence x = 1/2, y = 1/3

Hope this helps you