Question

х+у= 5xy.

3x+2y = 13xy elimination method
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Answer 1

Answer:

Please forgive my handwriting cause it's bad right now cause I thought u were in a hurry and I sent pics, Sir please do mark my answer Brainliest

Answer 2

$\bold\red{\underline{\underline{Answer:}}}$

$\bold{Value \ of \ x \ is \frac{1}{2} \ and}$

$\bold{y \ is \frac{1}{3}}$

$\bold\orange{Given:}$

$\bold{The \ given \ equations \ are}$

$\bold{=>x+y=5xy}$

$\bold{=>3x+2y=13xy}$

$\bold\green{\underline{\underline{Solution}}}$

$\bold{The \ given \ equations \ are}$

$\bold{=>x+y=5xy...(1)}$

$\bold{=>3x+2y=13xy...(2)}$

$\bold{Multiply \ eq(1) \ by \ 2, \ we \ get}$

$\bold{=>2x+2y=10xy...(3)}$

$\bold{Subtract \ eq(3) \ from \ eq(2) \ we \ get}$

$\bold{=>x=3xy}$

$\bold{Substitute \ value \ of \ x \ in \ eq(1) \ we \ get}$

$\bold{=>y=2xy}$

________________________________

$\bold{=>x=3xy}$

$\bold{=>\frac{x}{x}=3y}$

$\bold{=>3y=1}$

$\bold{=>y=\frac{1}{3}}$

________________________________

$\bold{=>y=2xy}$

$\bold{=>\frac{y}{y}=2x}$

$\bold{=>2x=1}$

$\bold{=>x=\frac{1}{2}}$

$\bold\purple{\tt{\therefore{Value \ of \ x \ is \frac{1}{2} \ and}}}$

$\bold\purple{y \ is \frac{1}{3}}$