Math, asked by farzeenqamar, 1 year ago

5xy+3z÷2a^3-c^2 when x=2, y=-1, z=3, a=4 and c=1/3

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Answered by madhu26798

5(2)(-1)+3(3)÷2(4)^3-(1/3)^3

madhu26798: =0.1111111

farzeenqamar: then?

madhu26798: (-1)÷(128-0.1111111)=0.00781928

madhu26798: is this ans crt?????

farzeenqamar: honestly speaking the book's answer key says its -9/1151 but that is not possible i guess

madhu26798: my calculation is this I don't know whether its crt or wrong I say tom

farzeenqamar: but your calculations seem right and understandable to me I'm doing it this way eck with the answer key sis tysm for helping

madhu26798: its k fne and tqs

farzeenqamar: :)

madhu26798: k bye

Answered by waizmalick

Answer:

5xy+3z÷2a^3-c^2 when x=2, y=-1, z=3, a=4 and c=1/3

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