5y +1/5y=?????????????
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Here is your answer may this helps you.
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Step-by-step explanation:
5y + 1/5y =6
Squaring both sides
(5y + 1/5y)²=6²
a²+b²+2ab
(5y)²+(1/5y)²+2 into 5y into 1/5y =(6)²
(25y²+1/25y²)+2 =36
25y²+1/25y²= 36–2
25y²+1/25y²=34
Subracting 2 from both sides
25y²+1/25y²-2 = 34–2
(5y)²+1/5y²) -2 =32
It include the identity :
a²+b²-2ab = (a-b)²
(5y - 1/5y )² = 32
5y - 1/5y = 32 under square root
=under square root 2×2×2×2×2
One two is not in pair
Hence the answer is 4under root 2
Hope it will help you.
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