5y+10=4y-10 ,find y with out transport
Answers
Answer:
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Step-by-step explanation:
Put different values of y in the given equation 5y+10=4y−10.
5(5)+10=4(5)−10
35
=10
5(−5)+10=4(−5)−10
−15
=−30
5(10)+10=4(10)−10
60
=30
5(−10)+10=4(−10)−10
−40
=−50
5(15)+10=4(15)−10
85
=50
5(−15)+10=4(−15)−10
−65
=−70
5(20)+10=4(20)−10
110
=70
5(−20)+10=4(−20)−10
−90=−90
Therefore, the value of y is −20.
Answer:
ANSWER
Put different values of y in the given equation 5y+10=4y−10.
5(5)+10=4(5)−10
35
=10
5(−5)+10=4(−5)−10
−15
=−30
5(10)+10=4(10)−10
60
=30
5(−10)+10=4(−10)−10
−40
=−50
5(15)+10=4(15)−10
85
=50
5(−15)+10=4(−15)−10
−65
=−70
5(20)+10=4(20)−10
110
=70
5(−20)+10=4(−20)−10
−90=−90
Therefore, the value of y is −20.