Question

5y^2-27y+10 fractorise

Answer 1

Answer:

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Step-by-step explanation:

STEP

1

:

Equation at the end of step 1

(5y2 - 27y) + 10

STEP

2

:

Trying to factor by splitting the middle term

2.1 Factoring 5y2-27y+10

The first term is, 5y2 its coefficient is 5 .

The middle term is, -27y its coefficient is -27 .

The last term, "the constant", is +10

Step-1 : Multiply the coefficient of the first term by the constant 5 • 10 = 50

Step-2 : Find two factors of 50 whose sum equals the coefficient of the middle term, which is -27 .

-50 + -1 = -51

-25 + -2 = -27 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -25 and -2

5y2 - 25y - 2y - 10

Step-4 : Add up the first 2 terms, pulling out like factors :

5y • (y-5)

Add up the last 2 terms, pulling out common factors :

2 • (y-5)

Step-5 : Add up the four terms of step 4 :

(5y-2) • (y-5)

Which is the desired factorization

Final result :

(y - 5) • (5y - 2)