Question

5Y/2-x/3=8;y/2+5X/3=12
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Answer 1

$\frac{5y}{2} - \frac{x}{3} = 8 \\ = > \frac{15y - 2x}{6} = 8 \\ = > 15y - 2x = 6 \times 8 \\ = > 15y - 2x = 48...........(1) \\ \\ \frac{y}{2} + \frac{5x}{3} = 12 \\ = > \frac{3y + 10x}{6} = 12 \\ = > 3y + 10x = 12 \times 6 \\ = > 3y + 10x = 36.........(2) \\ = > 10x = 36 - 3y \\ = > x = \frac{36 - 3y}{10} ......(3) \\ \\ now \: put \: the \: value \: of \: x \: in \: equation \: (1) \\ \\ = > 15y - 2x = 48 \\ = > 15y - 2 \times ( \frac{36 - 3y}{10} ) = 48 \\ = > 15y - \frac{36 - 3y}{5} = 48 \\ = > \frac{75y -( 36 - 3y)}{5} = 48 \\ = > \frac{75y - 36 + 3y}{5} = 48 \\ = > 75y - 36 + 3y = 48 \times 5 \\ = > 78y - 36 = 240 \\ = > 78y = 240 - 36 \\ = > 78y = 204 \\ = > y = \frac{204}{78} \\ = > y = \frac{102}{39} \\ \\ now \: put \: the \: value \: y \: n \: equation \: (3) \\ \\ = > x = \frac{36 - 3y}{10} \\ = > x = \frac{36 - \frac{102}{39} }{10} \\ = > x = \frac{ \frac{1404 - 102}{39} }{10} \\ = > x = \frac{ \frac{1302}{39} }{10} \\ = > x = \frac{1302}{39} \times \frac{1}{10} \\ > x = \frac{1302 }{390 } \\ = > x = \frac{217}{65}$

I hope that helps you