Question

5y + 4 = 3y + 6

5t + 3 = 2t + 15

6k + 5 = 2k + 1

8s - 1 = 2k + 1

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Answer 1

Answer:

Solve for the first variable in one of the equations, then substitute the result into the other equation.

s=0,k=−1,t=4,y=1