Question

(5y-4)/6 + (3y+10)/2 = 4y+1

Answer 1

Answer:

2

Step-by-step explanation:

1) [(5y - 4)/6] + [(3y + 10)/2] = 4y + 1.

2) Finding LCM of Denominators in RHS.

3) LCM = 6.

4) (5y - 4 + 9y + 30)/6 = 4y + 1.

5) Multiplying 6 on both sides of the equation.

6) 14y + 26 = 24y + 6

7) 10y = 20

8) y = 2

Answer 2

Answer is 2.

Step-by-step explanation:

[(5y - 4)/6] + [(3y + 10)/2] = 4y + 1.

Now Finding LCM of Denominators in RHS.

LCM = 6.

(5y - 4 + 9y + 30)/6 = 4y + 1.

Multiplying 6 on both sides of the equation.

14y + 26 = 24y + 6

10y = 20

y = 2

Hence, y=2.