Math, asked by simranpreet32564, 6 hours ago

5y^ - 40yz - 100z^/y-10z​

Answers

Answered by magentagamer44
0

Answer:

5 (y - 10 z)^0 (y + 2 z)

Step-by-step explanation:

Simplify the following:

(5 y^2 - 40 y z - 100 z^2)/(y - 10 z)

Factor 5 out of 5 y^2 - 40 y z - 100 z^2:

(5 (y^2 - 8 y z - 20 z^2))/(y - 10 z)

The factors of -20 that sum to -8 are 2 and -10. So, y^2 - 8 y z - 20 z^2 = (y + 2 z) (y - 10 z):

(5 (y + 2 z) (y - 10 z))/(y - 10 z)

Combine powers. (5 (y + 2 z) (y - 10 z))/(y - 10 z) = 5 (y - 10 z)^(1 - 1) (y + 2 z):

5 (y - 10 z)^(1 - 1) (y + 2 z)

1 - 1 = 0:

Answer: 5 (y - 10 z)^0 (y + 2 z)

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