Question

5y ki power 5 - 405y

Answer 1

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Here is your answer
$5y {}^{5} - 405y \\ = 5y( {y}^{4} - 81) \\ = 5y((y{}^{2} ) {}^{2} - 9 {}^{2} ) \\ = 5y( {y}^{2} - 9)( {y}^{2} + 9) \\ = 5y( {y}^{2} - {3}^{2} )( {y}^{2} + 9) \\ = 5y(y - 3)(y + 3)( {y}^{2} + 9)$

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