Question

5y²+12y-9=0 find the zeroes and verify​

Answer 1

Answer:

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Answer 2

Answer:

$5 {y}^{2} + 12y - 9 = 0 \\ \\ 5 {y}^{2} + 15y - 3y - 9 = 0 \\ \\ 5y(y + 3) - 3(y + 3) \\ \\ = (5y - 3)(y + 3) \\ \\ 5y - 3 = 0 \\ 5y = 3 \\ \\ y = \frac{3}{5} \\ \\ \\ y + 3 = 0 \\ \\ y = - 3$

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