Question

5y²+40y+80 following the factories​

Answer 1

$\huge\bf\underline\green{Answer}$

$= {5y}^{2} + 40y + 80$

$=5( {y}^{2} + 8y + 16)$

$=5 {(y + 4)}^{2}$

Answer 2

Factor

5

out of

5

y

2

+

40

y

+

80

.

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5

(

y

2

+

8

y

+

16

)

Factor using the perfect square rule.

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Rewrite

16

as

4

2

.

5

(

y

2

+

8

y

+

4

2

)

Check that the middle term is two times the product of the numbers being squared in the first term and third term.

8

y

=

2

⋅

y

⋅

4

Rewrite the polynomial.

5

(

y

2

+

2

⋅

y

⋅

4

+

4

2

)

Factor using the perfect square trinomial rule

a

2

+

2

a

b

+

b

2

=

(

a

+

b

)

2

, where

a

=

y

and

b

=

4

.

5

(

y

+

4