5year ago amit was 3 times as old as armann.10 year later amit is twice as old as armann.how old are ther now
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Let the age of Amit be x and Arman be y.
A/q
![(x - 5) = 3(y - 5) \\ x - 5 = 3y - 15 \\ x - 3y = - 15 + 5 \\ x - 3y = - 10.......(1) (x - 5) = 3(y - 5) \\ x - 5 = 3y - 15 \\ x - 3y = - 15 + 5 \\ x - 3y = - 10.......(1)](https://tex.z-dn.net/?f=%28x+-+5%29+%3D+3%28y+-+5%29+%5C%5C+x+-+5+%3D+3y+-+15+%5C%5C+x+-+3y+%3D++-+15+%2B+5+%5C%5C+x+-+3y+%3D++-+10.......%281%29)
After ten year..
Means..
According to the question...
![x + 10 = 2(y + 10) \\ x + 10 = 2y + 20 \\ x - 2y = 10.......(2) x + 10 = 2(y + 10) \\ x + 10 = 2y + 20 \\ x - 2y = 10.......(2)](https://tex.z-dn.net/?f=x+%2B+10+%3D+2%28y+%2B+10%29+%5C%5C+x+%2B+10+%3D+2y+%2B+20+%5C%5C+x+-+2y+%3D+10.......%282%29)
From equation 1 we get,
![x - 3y = - 10 \\ x = - 10 + 3y.......(3) x - 3y = - 10 \\ x = - 10 + 3y.......(3)](https://tex.z-dn.net/?f=x+-+3y+%3D++-+10+%5C%5C+x+%3D++-+10+%2B+3y.......%283%29)
Putting value of x in equation 2,we get
![x - 2y = 10 \\ ( - 103y) - 2y = 10 \\ y - 10 = 10 \\ y = 20years x - 2y = 10 \\ ( - 103y) - 2y = 10 \\ y - 10 = 10 \\ y = 20years](https://tex.z-dn.net/?f=x+-+2y+%3D+10+%5C%5C+%28+-+103y%29+-+2y+%3D+10+%5C%5C+y+-+10+%3D+10+%5C%5C+y+%3D+20years)
Putting value of y in equation 3
![x = - 10 + 3y \\ x = - 10 + 3 \times 20 \\ x = - 10 + 60 \\ x = 50 x = - 10 + 3y \\ x = - 10 + 3 \times 20 \\ x = - 10 + 60 \\ x = 50](https://tex.z-dn.net/?f=x+%3D++-+10+%2B+3y+%5C%5C+x+%3D++-+10+%2B+3+%5Ctimes+20+%5C%5C+x+%3D++-+10+%2B+60+%5C%5C+x+%3D+50)
Hence,
Age of Amit=50 years
Age of Arman=20 years..
A/q
After ten year..
Means..
According to the question...
From equation 1 we get,
Putting value of x in equation 2,we get
Putting value of y in equation 3
Hence,
Age of Amit=50 years
Age of Arman=20 years..
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