Math, asked by justinfrancis, 1 year ago

5years ago, a man was 7 time as old as his son. 5years,hence father will be 3times old as his son. find their present ages

Answers

Answered by mubaraka83
5
Let the past age of son = x Let the past age of father = 7x So, Present ages are x+5 and 7x+5 Future age of son = x+10 Future age of father = 7x+10 Given7x+10 = 3*(x+10) 7x+10 = 3x+30 7x-3x = 30-10 4x = 20 x = 20/4 x = 5 7x = 35 x+5 = 10 7x+5 = 40
Similar questions