5years ago,a man was 7times as old as his son.five years hence three times as old as his son. find their present age?
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5years ago,a man was 7times as old as his son.five years hence three times as old as his son. find their present age?
F-5 = 7(S-5)
F+5 = 3(S+5) ,
F- 7S = -30
F - 3S = 10
Solve to find the value of S
4S = 40
Age of son would be = 10 yrs
to find the value of F
F- 5 = 7(S-5)
F- 5 = 7(10-5)
F= 7*5+5 = 40 years Age of Father
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