5years ago, the age of father was 7 times the age of his son . After 5 years ,the age of the father will be 3 times the age of his son from now. How old are the father and his son now?
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Here's u go
Man = 40, Son = 10
Step-by-step explanation:
Define x:
Let x be the age of the son 5 years ago
The man = 7x
Find their present age now:
Son = x + 5
Man = 7x + 5
Find their age 5 years later:
Son = x + 5 + 5 = x + 10
Man = 7x + 5 + 5 = 7x + 10
Solve x:
The Man is 3 times as old as his son
7x + 10 = 3(x + 10)
7x + 10 = 3x + 30
4x = 20
x = 5
Find their present age:
Son = x + 5 = 5 + 5 = 10 years old
Man = 7x + 5 = 7(5) + 5 = 40 years old
Answer: The man is 40 and the son is 10 years old.
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Here's u go
Man = 40, Son = 10
Step-by-step explanation:
Define x:
Let x be the age of the son 5 years ago
The man = 7x
Find their present age now:
Son = x + 5
Man = 7x + 5
Find their age 5 years later:
Son = x + 5 + 5 = x + 10
Man = 7x + 5 + 5 = 7x + 10
Solve x:
The Man is 3 times as old as his son
7x + 10 = 3(x + 10)
7x + 10 = 3x + 30
4x = 20
x = 5
Find their present age:
Son = x + 5 = 5 + 5 = 10 years old
Man = 7x + 5 = 7(5) + 5 = 40 years old
Answer: The man is 40 and the son is 10 years old.
Mark me Brainliest I need 2 more
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