Question

√6^0+1/3=(0.75)^2x-3​

Answer 1

Answer:

$\sqrt{ {6}^{0} } \: + \: \frac{1}{3} \: = \: ( \frac{3}{4} ) ^{2x - 3}$

1 + 1/3 = (3/4)2x-3

$\frac{3 + 1}{3} = \: (\frac{3}{4}) ^{2x - 3}$

4/3 = (3/4)2x-3

We know, when we reciprocal a number, it's power becomes negative

So,

(3/4)¯¹ = (3/4)2x-3

As the numbers are same so we will compare the powers

-1 = 2x - 3

2x = 3-1

2x = 2

x = 2/2

x=1

Hope it helped you

#be brainly