Math, asked by seoshrebose20141239, 4 months ago

(6^0 - (2^0) * (6^0+2^0) is equal to

Answers

Answered by sehgalp381
18

Answer:

(6 {}^{0}  - 2 {}^{0} ) \times (6 {}^{0}  + 2 {}^{0} ) \\( 0 -0) \times (0 + 0) \\ 0

this is answer is 0

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