Question

(6^0 - (2^0) * (6^0+2^0) is equal to

Answer 1

Answer:

$(6 {}^{0} - 2 {}^{0} ) \times (6 {}^{0} + 2 {}^{0} ) \\( 0 -0) \times (0 + 0) \\ 0$

this is answer is 0