Question

تم
6-0 22x1020
molecules of urea arepresent
in looml solution. Reconcentration of
solution is​

Answer 1

Explanation:

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Home / Answer please! 6.02 x 1020molecules of urea are present in 100 mL of its solution. The concentration of the solution is:

6.02 x 1020 molecules of urea are present in 100 mL of its solution. The concentration of the solution is:

Option 1) 0.01 M Option 2) 0.001M Option 3) 0.1M Option 4) 0.02M

Answers (1)

P Plabita

Answered 2 years, 3 months ago

As learnt in

Molarity -

Molarity (M) = (Number of moles of solute)/(volume of solution in litres)

- wherein

It is defined as the number of moles of the solute in 1 litre of the solution.

No. of molecules (given) =

No. of moles =

Volume of solution=100 ml= 0.1 L

Therefore, Molarity=

10

−

3

0.1

=

0.01

M

Answer 2

Answer:

0.01M

Explanation:

Moles of urea = molecules/avogadro no

No. of molecules (given) = 6.022

No. of moles = 6.02×10^20/6.02×10^23=10^-3

Volume of solution=100 ml= 0.1 L

Therefore, Molarity= no of moles/volume

= 10^-3 / 0.1

= 0.01 M