(6^0+7^0)×(6^0-7^0) find the value of each of the following
Answers
Answered by
4
Anything to power of 0 is 1. Hence (1+1)×(1-1) = 2×0 = 0
Answered by
7
heya!
here's your answer!
____________
______
I would like to evaluate each bracket one by one then then I'll multiply both:-
first brackets:-
6^0 = 1
and 7^0 = 1
therefore ,
1+1 = 2
the Answer of first bracket = 2
second brackets:-
6^0 = 1
and 7^0 = 1
and 1-1 = 0
therefore second brackets' value = 0
now when we multiply both the answers
2 x 0 = 0
hence,
ANSWER is zero
Hope that this helps you:)
here's your answer!
____________
______
I would like to evaluate each bracket one by one then then I'll multiply both:-
first brackets:-
6^0 = 1
and 7^0 = 1
therefore ,
1+1 = 2
the Answer of first bracket = 2
second brackets:-
6^0 = 1
and 7^0 = 1
and 1-1 = 0
therefore second brackets' value = 0
now when we multiply both the answers
2 x 0 = 0
hence,
ANSWER is zero
Hope that this helps you:)
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