Question

6.0 g of urea is decomposed by 2M NaOH. volume of 2M NaOH required is​

Answer 1

Answer ⇒  Volume of solution = 50 mL.

Explanation ⇒

Mass of Urea = 6 grams.

Using the formula,

Molarity = No. of moles of urea/Volume of solution.

∴ 2 = No. of moles of Urea/Volume of solution.

No. of moles of urea = mass/molecular mass of urea.

∴ No. of moles = 6/60

∴ No. of moles = 0.1 moles.

∴ Volume of solution = 0.1/2

∴ Volume of solution = 0.05 L.

∴ Volume of solution = 50 mL.

Hope it helps.

Answer 2

Answer:

Answer ⇒  Volume of solution = 50 mL.

Explanation ⇒

Mass of Urea = 6 grams.

Using the formula,

Molarity = No. of moles of urea/Volume of solution.

∴ 2 = No. of moles of Urea/Volume of solution.

No. of moles of urea = mass/molecular mass of urea.

∴ No. of moles = 6/60

∴ No. of moles = 0.1 moles.

∴ Volume of solution = 0.1/2

∴ Volume of solution = 0.05 L.

∴ Volume of solution = 50 mL.

Hope it helps.