Question

Ā=6.00î – 8.00j units, B = 8.002 +3.00)
units and C = 26.0î +19.0j units. If
aĀ+bB+C =0, the values of a and b are
1)111÷123 and -161÷41
2)111÷123and 161÷41
3)-111÷123 and -161÷41
4)-111÷123 and 161÷41​

Answer 1

Explanation:

Since the given are vectors

• a(6i-8j)+b(8i+3j)+(26i+19j)=0

Now separating the components u get

1. (6a+8b+26)i+(-8a+3b+19)j=0
2. Now solving the above two equation u get the answer
3. That is, 6a+8b+26=0 and. - 8a+3b+19=0