Question

6.02*10^24 molecules of n2 reacts with 2.24*10^3 ml of o2 to form N2O5
Use the given chemical equation:
2N2+5O2------------>2N2O5
answer the following;
1.calculate maximum no. of moles of N2O5
2.find the volume of N2O5 produced at STP
3.Which reactant was present in excess during this reaction

Answer 1

Answer:

sorry I don't know

Explanation:

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