6.02*10^24 molecules of n2 reacts with 2.24*10^3 ml of o2 to form N2O5
Use the given chemical equation:
2N2+5O2------------>2N2O5
answer the following;
1.calculate maximum no. of moles of N2O5
2.find the volume of N2O5 produced at STP
3.Which reactant was present in excess during this reaction
Answers
Answered by
0
Answer:
sorry I don't know
Explanation:
please mark me as brainliest
Similar questions