Question

6.02×10²0 molecules of urea are present in 100ml of its Solution . The concentration of solution is .

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Answer 1

$\huge\mathbb {QUESTION-}$

$\sf{6.02×10^{20}}$ molecules of urea are present in 100ml of its Solution . The concentration of solution is .

$\Huge\mathbb{SOLUTUON-}$

$\large\underline{\underline{\sf Given:}}$

• $\sf{6.02×10^{20}}$ urea present in 100mL of Solution

$\large\underline{\underline{\sf To\:Find:}}$

• Concentration of Solution.

Number of molecules of Urea = $\sf{6.02×10^{20}}$

⛬ Number of moles = ${\sf \dfrac{Number\:of\:molecules}{N_A}}$

$\implies{\sf \dfrac{6.02×10^{20}}{6.02×10^{23}}}$

$\implies{\sf 1×10^{-3}mol}$

Volume of Solution

$\implies{\sf 100mL}$

$\implies{\sf \dfrac{100}{1000}L }$

$\implies{\sf 0.1L }$

Concentration of Urea solution

$\implies{\sf \dfrac{1×10^{-3}}{0.1} }$

$\implies{\sf 1×10^{-2}molL^{-1}}$

$\implies{\bf \red{0.01 molL^{-1}}}$

$\Huge\mathbb{ANSWER-}$

Concentration of Solution is ${\bf \red{0.01 molL^{-1}}}$

Answer 2

Answer:

0.01 mole is the concentration of solution