Question

6.02 x 10^20 molecules of urea are present in 100 mL of its solution. The concentration of solution

Answer 1

Moles of urea = molecules/avogadro no

=6.02X10^20 / 6.022 X 10^23

=10^-3 moles

So it will have 10^-2 mole in 1 litre of solution because

Molarity/concentration=mole / litre

= 10^-3/1L

=10^-2M