Question

6.02 x 10^20 molecules of urea are present in 100mL of its solution. the conc of solution is

Answer 1

⏬ Hello Friend Here Is Your Answer ⏬

Moles of urea = molecules/avogadro no

                       =    6.02X10^20 / 6.022 X 10^23

                       =          10^-3 moles

So it will have 10^-2 mole in 1 litre of solution

because 

Molarity/concentration = mole / litre

                                         = 10^-3/1L

                                        =    10^-2M

*hope it helped you*

Answer 2

Answer is
${10}^{ - 2} molar$
Refer photo for steps.
Hope this helps!