Question

6.022×10^23 molecules of N2 at NTP will occupy a volume of
(A)22.4 liters
(B)2.2 litres
(C)6.02 litres
(D)6.02 ml​

Answer 1

Answer:

avagadro no. =6.022*10²³

-> no. of molecules/ avagadro no. = volume/22.4

-> 6.022*10²³/6.022*10²³ =volume/22.4

-> volume =22.4 litre

Answer 2

Explanation:

The volume occupied by the 1mole of N

2

=22.4l

So, the 1mole=6.022×10

23

molecules of N

2

=

6.022×10

23

22.4

So, 6.022×10

22

molecules of N

2

would occupy volume

=

6.022×10

23

l

22.4

×6.022×10

22

=2.24l