Question

6.022 *10²³ molecules of N2at NTP will occupy yhe volume of

Answer 1

Q.$6.022 ×10^{23}$ molecules of $N_2$ will occupy the volume of.

Ans:- 22.4 l

Explanation:-

According to the Berzelius hypothesis "all gases contain equal number of atoms under similar conditions of temperature and pressure".

$1 mole = 6.022× 10^{23}molecules = 22.4l at N.T.P$

I. e, all gases in 1 mole occupies 22.4 l of volume at N. T. P

$\therefore$$6.022×10^{23} molecules \:of N_2 at \:N. T. P \: will occupy \: the \: volume\: of \: 22.4 l$