Question

6.023×10to the power 24 no of so2 molecules in ___L​

Answer 1

Answer:

224 L

Explanation:

no. of moles, n = No. of molecules÷ Nₐ

n= 6.022× 10²⁴ ÷6.022×10²³

n=10 moles

We know that, n= volume of gas @ NTP(L) 22.4 L

Volume of SO₂ @NTP= 10×22.4 L= 224 L