Question

6.023 x 10^20 atoms of silver weight is

Answer 1

1 mole of silver weighs 108 grams.
which implies 1 atom weighs
$1 \div 6.023 \times {10}^{23}$
Therefore
$6.023 \times {10}^{20}$
atoms weighs
${10}^{ - 3}$
grams.

Answer 2

Answer:

0.108g is the right answer

Explanation:

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