Question

6.023 x 10^23molecules of Ca (OH)2 react with 3.01x10^22 molecules of HCI, calculate the number of moles
of CaCl2 obtained.​

Answer 1

Explanation:

Number of molecules of HCl is less than Ca(OH)2

Hence, HCl is the limiting reagent.

So, 3.01 × 10²² molecules of CaCl2 is obtained.

Hope it helps.

Answer 2

Answer:

0.05 moles

Explanation:

there are lesser molecules of HCl than Ca(OH)2. so HCl is the limiting reagent.

hence, 3.01*10^22 molecules of  Ca(OH)2 is obtained.

3.01*10^22 = 1 mole/20

                  = 0.05 moles