Question

6.0g of sodium hydroxide is dissolved in 100g of water . Calculate the mass percent of sodium hydroxide in this solution

Answer 1

Explanation:

Mass of solute (NaOH) =6.0 gm.

Mass of solvent (water) =100 gm.

Mass of solution=(6.0+100) gm.

=106 g,

Therefore, Mass % (solution) =[Mass(solute)/Mass(solvent)] ×100

=[6g/(100+6)] ×100

= 6×100/100+6

= 600/100

= 5.66%

Answer 2

Answer:

The mass percent of sodium hydroxide in the solution will be equal to 5.66%.

Explanation:

We have given,

The mass of sodium hydroxide (solute) = 6g

The mass of water (solvent) = 100g

Total mass of the solution is equal to the sum of mass of solute and solvent.

Mass of solution = Mass of NaOH + Mass of water

Mass of solution = 100 + 6 = 106g

The mass percent % of sodium hydroxide solution will be:

Mass % of solution = [Mass (NaOH)/Mass (water)] ×100

Mass % $=\frac{6}{106}*100=\frac{600}{106}=5.66\%$

Therefore, the mass percentage of sodium hydroxide solution is equal to 5.66%.