Question

6. 1,25,000 for 1/1/2

years at 8% per annum
annum compounded half-yearly.​

Answer 1

Given :-

• Principal Amount = Rs 1,25,000

• Rate per annum = 8 %

• Amount compounded half yearly .

• Time period = 1 1/2 years

To Find ;-

• Compound interest .

Solution

$\boxed{\rm{ \implies \; Amount \; = P[ 1 + \dfrac{\frac{R}{2} }{100}]^{2n} \times [ 1 + \dfrac{\frac{b\times R}{c \times 2}\ }{100}] }}$

• n denotes number of complete years .

• b and c denotes the fraction in time period .

Using the above mentioned formula :-

${\rm{ \implies \; Amount \; = 125000[ 1 + \dfrac{\frac{8}{2} }{100}]^{2(1)} \times [ 1 + \dfrac{\frac{1 \times 8}{2 \times 2}\ }{100}] }}$

${\rm{ \implies \; Amount \; = 125000[ \dfrac{208 }{200}]^{2} \times [ \dfrac{408 }{400}] }}$

${\rm{ \implies \; Amount \; = 125000[ \dfrac{42640 }{40000}] \times [ \dfrac{408 }{400}] }}$

${\rm{ \implies \; Amount \; = 125[ \dfrac{4264 }{4}] \times [ \dfrac{408 }{400}] }}$

${\rm{ \implies \; Amount \; = 125[ 1066] \times [ 1.02] }}$

${\rm{ \implies \; Amount \; = 135915 }}$

Amount - 135915