Question

(6−¹×3−²)+7−²



answer me please ​

Answer 1

$\frac{1}{6} \times \frac{1}{(3) {}^{2} } + \frac{1}{7 {}^{2} }$

$\frac{1}{6} \times \frac{1}{9} + \frac{1}{49}$

$\frac{1}{54} + \frac{1}{49}$

$\frac{49 + 54}{2646}$

$\frac{103}{2646}$