6(1/3) how it is a rational number?
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Step-by-step explanation:
So m³ and hence m must be divisible by 6. But n and m where co-prime so they can not have any factors in common so we have a contradiction. So 6^(1/3) must not be rational. Hence it is irrational
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Answer:
m3 and hence m must be divisible by 6. But n and m where co-prime so they can not have any factors in common so we have a contradiction. So 6^(1/3) must not be rational. Hence it is irrational.
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