Math, asked by pradeep9535461113, 2 months ago

(6,1)(8,2)(9,4)and(X,3)adre the consecutive vertices
of a parallelogram find the value of x

Answers

Answered by scs335570samith
1

Answer:

7

Step-by-step explanation:

Let ,

A = (6,1) B = (8,2) C =(9,4) D = (x,3)

We know that mid point of diagonals of a parallelogram is equal

i.e Mid point of AC = Mid point of BD

[ (6+9)/2 , (1+4)/2 ] = [ (8+x)/2 , (2+3)/2 ]

[ 15/2 , 5/2 ] = [ (8+x)/2 , 5/2 ]          

⇒ 15/2 = 8+x/2

15 = 8+x

x = 15 - 8

x = 7                                                                

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