(6,1)(8,2)(9,4)and(X,3)adre the consecutive vertices
of a parallelogram find the value of x
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1
Answer:
7
Step-by-step explanation:
Let ,
A = (6,1) B = (8,2) C =(9,4) D = (x,3)
We know that mid point of diagonals of a parallelogram is equal
i.e Mid point of AC = Mid point of BD
[ (6+9)/2 , (1+4)/2 ] = [ (8+x)/2 , (2+3)/2 ]
[ 15/2 , 5/2 ] = [ (8+x)/2 , 5/2 ]
⇒ 15/2 = 8+x/2
15 = 8+x
x = 15 - 8
x = 7
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