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1)
If S, = 1023 , r = 4, Find a
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1
Answer:
a=3
Step-by-step explanation:
Given'
summatin of first 5 G.P series, S5=1023
and common ratio, r=4
summation of G.P terms having n number of terms =\frac{a\times(r^n -1)}{r-1}r−1a×(rn−1)
hence, summation of first five terms = \frac{a\times(r^5 -1)}{r-1}r−1a×(r5−1)
1023 = \frac{a\times(4^5 -1)}{4-1}4−1a×(45−1)
a=\frac{1023\times 3}{4^5 -1}45−11023×3
a=3
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