Question

6, 10, 14 are in Arithmetic progression Find its 15th term.​

Answer 1

Step-by-step explanation:

Given:6, 10, 14 are in Arithmetic progression.

To find: Find its 15th term.

Solution:

nth term of AP is given by

$\boxed{\bold{a_n = a + (n - 1)d}}$

here

a= first term

d= common difference

n= term

In the given AP

a= 6

d= 4

(10-6=14-10=4)

n= 15

put these values to the formula

$a_{15} = 6 + (15 - 1)4 \\ \\ a_{15} = 6 + 14 \times 4 \\ \\ a_{15} = 6 + 56 \\ \\ a_{15} = 62$

Final Answer:

Fifteenth term of AP is 62.

Hope it helps you.

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