Question

6×10^22 molecules are present in 2.24 dm^3 of chlorine at s.t.p calculate the volume of sulphur dioxide gas at S.T.p which has 3×10^19 molecules​

Answer 1

Answer : The Volume of sulphur dioxide gas at STP which has 3 × 10¹⁹ molecules is 0.00111 liter / dm³

Explanation:

Given : molecules of sulphur dioxide at STP = 3× 10¹⁹

To find : Volume of Sulphur dioxide

No of molecules = Volume of gas ( liter ) / 22.4 × NA

3 × 10¹⁹ = Volume of gas / 22.4 × 6.023 × 10²³

Volume of gas = 3 × 10¹⁹ × 22.4 / 6.023 × 10²³

Volume of gas ( sulphur dioxide) = 11.15 × 10-⁴

Volume of sulphur dioxide = 0.00111 liter