Question

(√6+√11)² identify using the suitable identity​

Answer 1

Step-by-step explanation:

mark it as brainliest

\begin{gathered}so \: here \: \\ secA + tanA =x \\ ie \: tan \: A = x - sec \: A\end{gathered}

sohere

secA+tanA=x

ietanA=x−secA

\begin{gathered}so \: now \: using \\ 1 + tan ^{2} A = sec {}^{2} A \\ 1 + (x - sec \: A) {}^{2} = sec {}^{2} A \\ 1 + x {}^{2} + sec {}^{2} A - 2sec \: A.x = sec {}^{2} A \\ 1 + x {}^{2} - 2sec \: A.x = 0 \\ ie \: 1 + x {}^{2} = 2secA.x \\ sec \: A = 1 + x {}^{2} /2x \\ \\ \end{gathered}

sonowusing

1+tan

2

A=sec

2

A

1+(x−secA)

2

=sec

2

A

1+x

2

+sec

2

A−2secA.x=sec

2

A

1+x

2

−2secA.x=0

ie1+x

2

=2secA.x

secA=1+x

2

/2x

\begin{gathered}thus \: value \: of \: sec \: A \: (in \: terms \: of \: x) \: is \: 1 + x {}^{2} /2x \\ \end{gathered}

Answer 2

Answer:

hey here is your answer

pls mark it as brainliest pls

Step-by-step explanation:

$so \: here \\ ( \sqrt{6} + \sqrt{11} ) {}^{2} \\ so \: here \: ( \sqrt{6} + \sqrt{11} ) {}^{2} \: is \: in \: ( a + b) {}^{2} \\ so \: we \: know \: that \\ (a + b) {}^{2} = a {}^{2} + b {}^{2} + 2ab \\ hence \: accordingly \\ ( \sqrt{6 } + \sqrt{11} ) {}^{2} = ( \sqrt{6} ) {}^{2} + ( \sqrt{11} ) {}^{2} + 2 \times \sqrt{6} \times \sqrt{11} \\ = 6 + 11 + 2 \sqrt{66} \\ = 17 + 2 \sqrt{66}$