Question

6+12+18+24+ ... = 1800 then find number of terms in series

Answer 1

Answer:

sum is 1800

a=6

d=6

n/2{2a+(n-1)d=1800

n{12+6n-6}=3600

n(n+1)=600

n^2+n-600=0

n^2+25n-24n-600=0

n(n+25)-24(n+25)=0

(n-24)(n+25)=0

n=24

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