6, 12, 21, ?, 48
A.33
B.38
C.40
D.45
Answers
Answered by
11
The Answer is...
A.33
Pattern is +6, +9, +12, +15...
6 +6=12
12+9=21
Missing term : 21 +12=33
6+3+3=12
12+6+3=21
21+9+3=33
33+12+3=48
A.33
Pattern is +6, +9, +12, +15...
6 +6=12
12+9=21
Missing term : 21 +12=33
6+3+3=12
12+6+3=21
21+9+3=33
33+12+3=48
Answered by
4
hey, here is your answer......
Option.A is correct i.e., 33 is the correct answer......
here is the explanation.,
given, 6, 12, 21, ?, 48.......
==> 6 = 3×2......
==> 12 = 3×4......
==> 21 = 3×7.......
==> ? = 3×y.........
==> 48 = 3×16......
2, 4, 7, y, 16..... are in series such that.,
==> 4-2 = 2.....
==> 7-4 = 3.....
"y-7" should be equal to 4., and "16-y" should be equal to 5., because,
differences are in A.P with common difference 1..... so,
y-7 = 4.... ==> y = 11......
we got that, ? = 3×y......
==> ? = 3×11.... = 33.....
Therefore, required no. is 33......
hope this helps you......
thank you......
plzz mark me as brainliest.........
Option.A is correct i.e., 33 is the correct answer......
here is the explanation.,
given, 6, 12, 21, ?, 48.......
==> 6 = 3×2......
==> 12 = 3×4......
==> 21 = 3×7.......
==> ? = 3×y.........
==> 48 = 3×16......
2, 4, 7, y, 16..... are in series such that.,
==> 4-2 = 2.....
==> 7-4 = 3.....
"y-7" should be equal to 4., and "16-y" should be equal to 5., because,
differences are in A.P with common difference 1..... so,
y-7 = 4.... ==> y = 11......
we got that, ? = 3×y......
==> ? = 3×11.... = 33.....
Therefore, required no. is 33......
hope this helps you......
thank you......
plzz mark me as brainliest.........
Anonymous:
plzz mark me as brainliest Nabholin
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