6, 13, 38, ?, 532, 2675
Answers
TO FIND
the missing no in sequence
GIVEN
6,13,38,?,532,2675
STEP BY STEP SOLUTION
6×1 = 6
6×1+7×1 = 6+7 = 13
13×2+6×2 = 26+12 = 38
38×3+5×3 = 114+15 = 129
129×4+4×4 = 516+16 = 532
532×5+3×5 = 2660+15 = 2675
ANSWER
the unknown number is 129
Given:
A series of numbers 6, 13, 38,? , 532, 2675.
To Find:
The number which replaces the? is
Solution:
The given problem can be solved by developing a common logic between every term.
1. The second term in the sequence is obtained using the logic,
=> 13 = 6 x 1 + 7 x 1,
2. The third term in the sequence is obtained using the logic,
=> 38 = 13 x 2 + 6 x 2,
3. The sixth term in the sequence is obtained using the logic,
=> 2675 = 532 x 5 + 3 x 5,
4. Using the same pattern, the missing term can also be found,
=> Fourth term = 38 x 3 + 5 x 3,
=> Fourth term = 114 + 15,
=> Fourth term = missing term = 129.
5. The fifth term in the series is obtained using the relation,
532 = 129 x 4 + 4 x 4.
Therefore, the missing term is 129.