6.1f n(A) = 4, n (B)=5. n(AnB)=3, then n(
A x B) n(B x A) Is
(1) 8
(2) 9
(3) 10
(4)6
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Answer:
n(A) = 4
n(B)=5
n(AnB)=3
For (A×B)∩(B×A) we have to do the mapping of A×B or B×A between common elements.
no. of ways of mapping will be 3×3=9
n[(A×B)∩(B×A)]=9
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